Higher January 2020 Paper 2 Q10
10 Change a speed of 50 metres per second to a speed in kilometres per hour.
(3)
| Scheme | Marks |
|---|---|
50 × 60 (= 3000) or 50 ÷ 1000 (= 0.05 or \(\dfrac{1}{20}\)) or 50 × 60 × 60 (= 180 000) or \(\dfrac{60 \times 60}{1000}\) (= 3.6) or 1000 ÷ 60 ÷ 60 (= 0.27777…. or \(\dfrac{5}{18}\)) | M1 |
| \(50 \times \dfrac{60 \times 60}{1000}\) oe eg \(50 \div \dfrac{5}{18}\) | M1 |
| 180 | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for 50 with at least one of ÷ 1000 or × 60
or
\(\dfrac{60 \times 60}{1000}\) (= 3.6)
or
1000 ÷ 60 ÷ 60
M1: (dep) for a complete method
A1: for 180
(SCB1 for both conversion factors correct but applying them wrongly eg \(\dfrac{50 \times 1000}{60 \times 60}\))