Foundation November 2024 Paper 2 Q8
8
(a) Simplify \(\quad 7g + 3h + 4g - 5h\) (2)
(b) Simplify \(\quad 7a \times 4m\) (1)
(c) Solve \(\quad 5x - 7 = 12\) (2)
(d) Expand \(\quad 5(7k + 3)\) (1)
(e) Factorise \(\quad 9y + 12\) (1)
Max has \(c\) counters.
Bulan has 3 times as many counters as Max.
Chanda has 7 more counters than Max.
(f) Write an expression, in terms of \(c\), for the total number of counters that Max, Bulan and Chanda have.
Simplify your answer. (3)
Simplify your answer. (3)
| Scheme | Marks |
|---|---|
| \(11g - 2h\) | B2 |
| (2) |
Notes
B2: B1 for one correct term
(B1 for \(11g + -2h\))
| Scheme | Marks |
|---|---|
| \(28am\) | B1 |
| (1) |
Notes
B1: oe
| Scheme | Marks |
|---|---|
| \(5x = 12 + 7\) oe or \((12 + 7) \div 5\) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: 3.8 | A1 |
| (2) |
Notes
M1: A correct equation with number terms one side and \(x\) the other
or
for a correct process to find \(x\)
A1: oe \(\dfrac{19}{5}\) or \(3\dfrac{4}{5}\)
| Scheme | Marks |
|---|---|
| \(35k + 15\) | B1 |
| (1) |
Notes
B1: or \(15 + 35k\) allow \(35x + 15\)
| Scheme | Marks |
|---|---|
| \(3(3y + 4)\) | B1 |
| (1) |
Notes
B1: allow \(3(3y + 4\) or \(3(3x + 4)\)
| Scheme | Marks |
|---|---|
| \(3c\) (allow \(3 \times c\) or \(c3\)) or \(c + 7\) | M1 |
| \(c + 3c + c + 7\) | M1 |
| Correct answer scores full marks (unless from obvious incorrect working) Answer: \(5c + 7\) | A1 |
| (3) | |
| (10 marks) |
Notes
M1: allow \(3c + 7\)
M1: correct unsimplified expression
A1: allow \(5 \times c + 7\)