Foundation November 2020 Paper 2 Q14
14
(a) Factorise \(\;25f - 10\) (1)
(b) Make \(y\) the subject of the formula \(\;c = 5y - h\) (2)
(c) Solve the inequality \(\;4x + 7 \gt 2\) (2)
| Scheme | Marks |
|---|---|
| \(5(5f - 2)\) | B1 |
| (1) |
| Scheme | Marks |
|---|---|
| \(c + h = 5y\) or \(\dfrac{c}{5} = y - \dfrac{h}{5}\) or \(\dfrac{c + h}{5}\) | M1 |
| \(y = \dfrac{c + h}{5}\) | A1 |
| (2) |
Notes
A1: oe if the student puts \(\dfrac{c + h}{5}\) on the answer line then if we have previously see \(y = \dfrac{c + h}{5}\) we can award full marks
| Scheme | Marks |
|---|---|
| \(4x \gt 2 - 7\) oe or \(x + \dfrac{7}{4} \gt \dfrac{2}{4}\) oe | M1 |
| \(x \gt -1.25\) | A1 |
| (2) | |
| (5 marks) |
Notes
M1: accept as an equation or with wrong inequality sign.
A1: oe allow (−1.25, (+)\(\infty\))
Note: award M1A0 for an answer of −1.25 with no sign or the incorrect sign eg \(x = -1.25\), \(x \lt -1.25\)