Higher November 2021 Paper 2 Q8
8 The grouped frequency table gives information about the time, in minutes, taken by 50 people to solve a puzzle.
| Time (\(t\) minutes) | Frequency |
|---|---|
| \(0 \lt t \leqslant 10\) | 5 |
| \(10 \lt t \leqslant 20\) | 8 |
| \(20 \lt t \leqslant 30\) | 12 |
| \(30 \lt t \leqslant 40\) | 15 |
| \(40 \lt t \leqslant 50\) | 7 |
| \(50 \lt t \leqslant 60\) | 3 |
Brian was asked to draw a cumulative frequency table for this information.
This is the table that Brian drew.
| Time (\(t\) minutes) | Cumulative frequency |
|---|---|
| \(0 \lt t \leqslant 10\) | 5 |
| \(10 \lt t \leqslant 20\) | 13 |
| \(20 \lt t \leqslant 30\) | 25 |
| \(30 \lt t \leqslant 40\) | 40 |
| \(40 \lt t \leqslant 50\) | 47 |
| \(50 \lt t \leqslant 60\) | 50 |
Write down one thing that is wrong with this cumulative frequency table. (1)
| Answer | Mark | Mark scheme |
|---|---|---|
| Error in inequalites | C1 | for identifying incorrect inequalities Acceptable examples gives at least one correct inequality eg \((10 \lt t \leqslant 20)\) should be \(0 \lt t \leqslant 20\) it should be \(t \leqslant 20\) (all) inequalities should start with 0 should start with 0 Not acceptable examples \(10 \lt t \leqslant 20\) is wrong the numbers have been added wrong |