Higher November 2017 Paper 1 Q6
6 Here is a rectangle.
All measurements are in centimetres.
The area of the rectangle is \(48\text{ cm}^2\).
Show that \(y = 3\) (4)
| Answer | Mark | Notes | ||
|---|---|---|---|---|
| Shows reasoning to reach \(y=3\) | M1 | forms equation eg \(2x + 6 = 5x - 9\) | \(48 \div 3\ (=16)\) | \(3(2x + 6) = 48\) or \(3(5x - 9) = 48\), condone missing bracket |
| M1 | isolates \(x\) and number terms \(3x = 15\) | forms equation \(2x+6=\text{``}16\text{''}\) or \(5x - 9= \text{``}16\text{''}\) | Isolates \(x\) and number terms \(6x = \text{``}30\text{''}\) or \(15x = \text{``}75\text{''}\) | |
| M1 | substitutes “5” into side length eg \(2 \times 5 + 6\ (=16)\) | isolates \(x\) and number terms \(2x= \text{``}10\text{''}\) or \(5x = \text{``}25\text{''}\) | forms the second equation | |
| A1 | \(48 \div 16=3\) or \(16 \times 3=48\) | shows \(x=5\) for both solutions | \(x=5\) from 2 different equations. | |