Foundation June 2025 Paper 2 Q29
29 The first three terms of a Fibonacci sequence are
\(a\) \(3a\) \(4a\)
The 5th term of this sequence is 286
Work out the value of \(a\). (3)
| Answer | Mark | Mark scheme |
|---|---|---|
| 26 | M1 | for continuing the sequence to find the 5th term, eg \(3a + 4a + 4a\ (= 11a)\) |
| M1 | (dep M1) for equating the fifth term with 286, eg \(3a + 4a + 4a = 286\) oe or \(286 \div \text{``}11\text{''}\) | |
| A1 | cao |
Additional guidance
May be seen next to sequence
Award M2 for a correct numerical statement relating 26, 11 and 286
An answer of 26 coming from an incorrect method,
eg \(a + 3a + 4a + 7a + 11a = 26a\)
scores M1 only unless numerical statement relating 26, 11 and 286 with no \(a\) is seen