Foundation June 2018 Paper 1 Q16
16 \(P = 4x + 3y\)
\(x = 5\)
\(y = -2\)
(a) Work out the value of \(P\). (2)
(b) Expand \(4e(e + 2)\) (2)
(c) Solve \(3(m - 4) = 21\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| 14 | M1 | for \(4 \times 5\) and \(3 \times -2\), the substitution may be seen in two separate calculations, eg \(4 \times 5\ (= 20)\) and \(3 \times -2\ (= -6)\) |
| A1 | cao |
| Answer | Mark | Mark scheme |
|---|---|---|
| \(4e^2 + 8e\) | B2 | for \(4e^2 + 8e\) |
| (B1 | for \(4e^2\) or \(8e\)) |
Additional guidance
Note: \(4e^2 + 8e = 12e^3\) for example gets B1 only
| Answer | Mark | Mark scheme |
|---|---|---|
| 11 | M1 | for a correct first step eg \(3 \times m - 3 \times 4 = 21\) oe or \(m - 4 = 21 \div 3\ (= 7)\) oe |
| A1 | cao |
Additional guidance
Showing \(\div 3\) by each side of equation is sufficient