AS June 2022 Q1
1. Abena and Meghan are both given the same list of 10 films.
Each of them ranks the 10 films from most favourite to least favourite.
For the differences, \(d\), between their ranks for these 10 films, \(\sum d^2 = 84\)
A test is carried out at the 5% level of significance to see if there is agreement between their ranks for the films.
The hypotheses for the test are
\[\mathrm{H}_0 : \rho_\mathrm{S} = 0 \qquad \mathrm{H}_1 : \rho_\mathrm{S} \gt 0\]An 11th film is added to the list. Abena and Meghan both agree that this film is their least favourite.
A new test is carried out at the 5% level of significance using the same hypotheses.
| Scheme | Marks | AO |
|---|---|---|
| \(\left[r_s = 1 - \dfrac{6 \times 84}{10(10^2 - 1)}\right]\) \(= 0.4909\ldots\) awrt 0.491 | B1 | 1.1b |
| (1) |
Notes
B1: awrt 0.491 (allow \(\dfrac{27}{55}\))
| Scheme | Marks | AO |
|---|---|---|
| (i) \((1 \gt)\, r_s \gt 0.5636\) | B1 | 1.1b |
| (ii) (0.491 is not in the critical region) There is insufficient evidence of agreement between their film ranks. | B1ft | 2.2b |
| (2) |
Notes
(i) B1: Correct critical region with 0.5636 or better. Condone use of \(\rho\) instead of \(r_s\)
(ii) B1ft: Correct ft contextualised conclusion (must include film or ranks) based on their (a) and their CR Allow ft on their CV if a CR is not stated
| Scheme | Marks | AO |
|---|---|---|
| new \(r_s = 1 - \dfrac{6 \times 84}{11(11^2 - 1)}\) | M1 | 1.1b |
| \(= 0.61818\ldots\) awrt 0.618 | A1 | 1.1b |
| new critical value is 0.5364 | B1 | 1.1b |
| There is now sufficient evidence of agreement between their film ranks. | A1 | 2.2b |
| (4) | ||
| (7 marks) |
Notes
M1: Use of formula with same \(\sum d^2\) and 11
A1: awrt 0.618 (allow \(\dfrac{34}{55}\))
B1: 0.5364 or better
A1: fully correct solution with awrt 0.618 and contextualised conclusion (must include film or ranks)