AS June 2019 Q1
1. Bara is investigating whether or not the two judges of a skating competition are in agreement. The two judges gave a score to each of the 8 skaters in the competition as shown in the table below.
| Skater | ||||||||
|---|---|---|---|---|---|---|---|---|
| \(A\) | \(B\) | \(C\) | \(D\) | \(E\) | \(F\) | \(G\) | \(H\) | |
| Judge 1 | 71 | 70 | 72 | 62 | 63 | 61 | 57 | 53 |
| Judge 2 | 73 | 71 | 67 | 64 | 62 | 56 | 52 | 53 |
Bara decided to calculate Spearman’s rank correlation coefficient for these data.
Judge 1 accidentally swapped the scores for skaters \(D\) and \(E\). The score for skater \(D\) should be 63 and the score for skater \(E\) should be 62
| Scheme | Marks | AO | ||||||||||||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| M1 dM1 | 1.1b 1.1b | ||||||||||||||||||||||||||||||||||||
| \(\sum d^2 = 10\) | ||||||||||||||||||||||||||||||||||||||
| \(r_s = 1 - \dfrac{6 \times \text{“}10\text{”}}{8(64 - 1)}\) | M1 | 1.1b | ||||||||||||||||||||||||||||||||||||
| \(r_s = 0.8809\ldots\) awrt 0.881 | A1 | 1.1b | ||||||||||||||||||||||||||||||||||||
| (4) |
Notes
M1: For an attempt to rank at least one row ( at least 4 correct)
dM1: dep on previous M mark being awarded. For an attempt at \(d\) or \(d^2\) row for their ranks.
M1: for use of \(1 - \dfrac{6 \times \text{“their} \sum d^2\text{”}}{8(64 - 1)}\) Allow if not ranked \(\sum d^2 = 85\)
A1: awrt 0.881
| Scheme | Marks | AO |
|---|---|---|
| \(\mathrm{H}_0 : \rho = 0 \quad \mathrm{H}_1 : \rho \gt 0\) | B1 | 2.5 |
| Critical Value \(\rho = 0.8333\) | B1 | 1.1b |
| \(r_s = 0.8809\) lies in the critical region/reject \(\mathrm{H}_0\)/significant | M1 | 2.1 |
| There is evidence that the two judges are in agreement. | A1cso | 2.2b |
| (4) |
Notes
B1: Both hypotheses stated in terms of \(\rho\)
B1: for correct critical value. Allow even if 2 tail test (sign must match their \(r_s\))
M1: for comparing their 0.881 with “their 0.8333”
A1cso: All previous marks awarded. For a correct contextual conclusion with no contradictions seen
| Scheme | Marks | AO |
|---|---|---|
| The \(\sum d^2\) will decrease since the new rankings given by Judge 1 are now the same as the rankings given by Judge 2 for Skater D and E whereas previously they were different | M1 | 2.4 |
| therefore Spearman’s rank correlation coefficient will increase | A1 | 2.2a |
| (2) | ||
| (10 marks) |
Notes
M1: For a correct explanation to support their answer given.
\(\sum d^2\) decreases or \(d/d^2\) decreases for \(D\) and \(E\)
and idea of same rankings eg \(d^2\) will reduce by 2 . Do not allow \(d^2\) will reduce by 1
A1: for a correct deduction from the information. Allow closer to 1.