October 2021 Paper 3 Mechanics Q5
5. At time \(t\) seconds, a particle \(P\) has velocity \(\mathbf{v}\ \text{m s}^{-1}\), where
\[\mathbf{v} = 3t^{\frac{1}{2}}\,\mathbf{i} - 2t\,\mathbf{j} \qquad t \gt 0\]At time \(t\) seconds, where \(t \gt 0\), the position vector of \(P\), relative to a fixed origin \(O\), is \(\mathbf{r}\) metres.
When \(t = 1\), \(\mathbf{r} = -\mathbf{j}\)
| Scheme | Marks | AO |
|---|---|---|
| Differentiate \(\mathbf{v}\) wrt \(t\) | M1 | 3.1a |
| \(\dfrac{3}{2}t^{-\frac{1}{2}}\mathbf{i} - 2\mathbf{j}\) isw | A1 | 1.1b |
| (2) |
Notes
Allow column vectors throughout this question
M1: Both powers decreasing by 1 (M0 if vector(s) disappear but allow recovery)
A1: cao
| Scheme | Marks | AO |
|---|---|---|
| \(3t^{\frac{1}{2}} = 2t\) | M1 | 2.1 |
| Solve for \(t\) | DM1 | 1.1b |
| \(t = \dfrac{9}{4}\) | A1 | 1.1b |
| (3) |
Notes
Allow column vectors throughout this question
M1: Complete method, using \(\mathbf{v}\), to obtain an equation in \(t\) only, allow a sign error
DM1: Dependent on M1, solve for \(t\)
A1: cao
| Scheme | Marks | AO |
|---|---|---|
| Integrate \(\mathbf{v}\) wrt \(t\) | M1 | 3.1a |
| \(\mathbf{r} = 2t^{\frac{3}{2}}\mathbf{i} - t^2\mathbf{j}\ (+\mathbf{C})\) | A1 | 1.1b |
| \(t = 1\), \(\mathbf{r} = -\mathbf{j} \Rightarrow \mathbf{C} = -2\mathbf{i}\) so \(\mathbf{r} = 2t^{\frac{3}{2}}\mathbf{i} - t^2\mathbf{j} - 2\mathbf{i}\) | A1 | 2.2a |
| (3) |
Notes
Allow column vectors throughout this question
M1: Both powers increasing by 1 (M0 if vectors disappear but allow recovery)
A1: Correct expression without \(\mathbf{C}\)
A1: cao
| Scheme | Marks | AO |
|---|---|---|
| \(\sqrt{\left(3t^{\frac{1}{2}}\right)^2 + (2t)^2} = 10\) or \(\left(3t^{\frac{1}{2}}\right)^2 + (2t)^2 = 10^2\) | M1 | 2.1 |
| \(9t + 4t^2 = 100\) | M(A)1 | 1.1b |
| \(t = 4\) | A1 | 1.1b |
| \(\mathbf{r} = 14\mathbf{i} - 16\mathbf{j}\) | M1 | 1.1b |
| \(\sqrt{14^2 + (-16)^2}\) | M1 | 3.1a |
| \(\sqrt{452}\ \left(2\sqrt{113}\right)\) (m) | A1 | 1.1b |
| (6) | ||
| (14 marks) |
Notes
Allow column vectors throughout this question
M1: Use of Pythagoras on \(\mathbf{v}\) and 10 to set up equation in \(t\)
M(A)1: Correct 3 term quadratic in \(t\)
A1: cao
M1: Substitute their numerical \(t\) value into their \(\mathbf{r}\)
M1: Use of Pythagoras to find the magnitude of their \(\mathbf{r}\)
A1: cso