Higher November 2021 Paper 2 Q5
5 Solve \(\qquad 10x = 62.4 - 3x\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(10x + 3x\) or \(13x\) or \(-3x - 10x\) or \(-13x\) | M1 | may be implied eg \(62.4 \div 13\) or \(-62.4 \div -13\) |
| 4.8 or \(4\dfrac{4}{5}\) or \(\dfrac{24}{5}\) | A1 | oe eg \(\dfrac{624}{130}\) |
Additional guidance
| \(\dfrac{-24}{-5}\) | M1A0 |
| Correct answer embedded eg \(10 \times 4.8 = 62.4 - 3 \times 4.8\) | M1A0 |
| Ignore conversion attempt after correct answer seen |