Foundation November 2021 Paper 2 Q18
18 Solve \(\quad 10x - 3 = 21\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(10x = 21 + 3\) or \(10x = 24\) or \((21 + 3) \div 10\) or \(24 \div 10\) | M1 | oe eg \(-10x = -3 - 21\) |
| 2.4 | A1 | oe eg \(\dfrac{24}{10}\) or \(\dfrac{12}{5}\) or \(2\dfrac{4}{10}\) or \(2\dfrac{2}{5}\) SC1 1.8 oe |
Additional guidance
| \(10x - 3 + 3 = 21 + 3\) | M1 |
| \(10x - 3 = 21 + 3\) or \(10x - 3 + 3 = 21\) unless recovered | M0 |
| \(10x \div 10 - 3 \div 10 = 21 \div 10\) | M1 |
| \(10x \div 10 - 3 = 21 \div 10\) unless recovered | M0 |
| Embedded answer eg \(10 \times 2.4 - 3 = 21\) with no or incorrect answer | M1A0 |