Higher November 2020 Paper 3 Q15
15 Solve \(\quad 4 > 11 - \dfrac{x}{3}\) [2 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(\dfrac{x}{3} > 11 - 4\) or \(\dfrac{x}{3} > 7\) or \(4 - 11 > -\dfrac{x}{3}\) or \(-7 > -\dfrac{x}{3}\) or \(-21 > -x\) | M1 | oe term in \(x\) isolated |
| \(x > 21\) or \(21 < x\) | A1 | SC1 \(x = 21\) or \(x < 21\) or \(21 > x\) |
| Alternative method 2 | ||
| \(12 > 33 - x\) or \(x > 33 - 12\) or \(-12 < -33 + x\) | M1 | oe fractions eliminated eg \(12 - 33 > -x\) |
| \(x > 21\) or \(21 < x\) | A1 | SC1 \(x = 21\) or \(x < 21\) or \(21 > x\) |
Additional guidance
| Do not allow use of ‘=’ for M1 unless recovered for final answer | |
| \(12 > 11 - x\) | M0A0 |
| 21 on answer line with no working | M0A0 |