Higher November 2018 Paper 2 Q15
15 The volume of a medal is 45 cm3
The medal is made from copper and tin.
| volume of copper : volume of tin = 22 : 3 |
The density of copper is 8.96 g/cm3
The density of tin is 7.31 g/cm3
Work out the mass of the medal. [4 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(45 \div (22 + 3)\) or \(45 \div 25\) or 1.8 | M1 | oe eg \(\dfrac{45}{25}\) |
| \(22 \times \text{their } 1.8\) or 39.6 or \(3 \times \text{their } 1.8\) or 5.4 | M1dep | |
| \(\text{their } 39.6 \times 8.96 + \text{their } 5.4 \times 7.31\) or \([354, 355] + [39, 40]\) | M1dep | |
| 394.29 or 394.3 | A1 | |
| Alternative method 2 | ||
| \(45 \div (22 + 3)\) or \(45 \div 25\) or 1.8 | M1 | oe eg \(\dfrac{45}{25}\) |
| \(\text{their } 1.8 \times 8.96\) or [16.1, 16.13] or \(\text{their } 1.8 \times 7.31\) or [13.1, 13.2] | M1dep | |
| \(\text{their } [16.1, 16.13] \times 22\) \(+\; \text{their } [13.1, 13.2] \times 3\) or \([354, 355] + [39, 40]\) | M1dep | |
| 394.29 or 394.3 | A1 | |
| Alternative method 3 | ||
| \(45 \div (22 + 3)\) or \(45 \div 25\) or 1.8 | M1 | oe eg \(\dfrac{45}{25}\) |
| \(22 \times 8.96\) or [197, 197.12] or \(3 \times 7.31\) or [21.9, 22] | M1 | |
| \(\text{their } [197, 197.12] \times \text{their } 1.8\) \(+\; \text{their } [21.9, 22] \times \text{their } 1.8\) or \([354, 355] + [39, 40]\) | M1dep | oe dep on M1M1 |
| 394.29 or 394.3 | A1 | |
Additional guidance
Allow up to M2 even if not subsequently used
Ignore units throughout