Higher June 2024 Paper 1 Q23
23
(a) The first three terms of a geometric progression are \(\quad \dfrac{\sqrt{5}}{2} \qquad \dfrac{5}{4} \qquad \dfrac{5\sqrt{5}}{8}\)
Work out the next term. [1 mark]
(b) The \(n\)th term of a sequence is \(\quad (2 + \sqrt{3})^n\)
Show that the third term is \(\quad 26 + 15\sqrt{3}\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{25}{16}\) or \(1\dfrac{9}{16}\) | B1 | oe with no surds or indices |
Additional guidance
| Ignore an incorrect conversion of \(\dfrac{25}{16}\) to a mixed number | |
| \(\dfrac{5\sqrt{5}\sqrt{5}}{16}\) or \(\dfrac{5^2}{16}\) | B0 |
| Answer | Mark | Comments |
|---|---|---|
| \(4 + 2\sqrt{3} + 2\sqrt{3} + (\sqrt{3})^2\) or \(4 + 4\sqrt{3} + (\sqrt{3})^2\) or \(7 + 4\sqrt{3}\) | M1 | oe 4 terms with at least 3 correct or 3 terms with 2 correct including \(4\sqrt{3}\) terms may be seen in a grid |
| \(7 \times 2 + 7\sqrt{3} + 2 \times 4\sqrt{3} + 4\sqrt{3} \times \sqrt{3}\) or \(8 + 8\sqrt{3} + 6 + 4\sqrt{3} + 4 \times 3 + 3\sqrt{3}\) or \(14 + 7\sqrt{3} + 8\sqrt{3} + 12\) or \(8 + 4\sqrt{3} + 4\sqrt{3} + 6 + 4\sqrt{3} + 6 + 6 + 3\sqrt{3}\) | M1dep | oe full expansion with correct multiplication of their 2, 3 or 4 terms by \((2 + \sqrt{3})\) terms may be seen in a grid |
| \(8 + 4\sqrt{3} + 4\sqrt{3} + 6 + 4\sqrt{3} + 6 + 6 + 3\sqrt{3}\) and \(26 + 15\sqrt{3}\) or \(14 + 7\sqrt{3} + 8\sqrt{3} + 12\) and \(26 + 15\sqrt{3}\) | A1 | oe with full expansion terms may be seen in a grid condone \(15\sqrt{3} + 26\) |
Additional guidance
Remember that the answer is given in the question
3 may be seen as \((\sqrt{3})^2\) for M1 only
Condone missing brackets if multiplications are correct