Higher June 2018 Paper 1 Q6
6 The height of Zak is 1.86 metres.
The height of Fred is 1.6 metres.
Write the height of Zak as a fraction of the height of Fred.
Give your answer in its simplest form. [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(\dfrac{1.86}{1.6(0)}\) | M1 | oe \(\dfrac{0.93}{0.8(0)}\) or \(1\dfrac{0.26}{1.6}\) |
| \(\dfrac{186}{160}\) or \(1\dfrac{26}{160}\) | A1 | oe with no decimal values |
| \(\dfrac{93}{80}\) or \(1\dfrac{13}{80}\) | B1ft | ft correct simplification of their fraction using the digits 186 and 16(0) ignore incorrect conversion from \(\dfrac{93}{80}\) to a mixed number |
Additional guidance
| Cannot score B1ft from an incorrect mixed number | |
| \(\dfrac{160}{186} = \dfrac{80}{93}\) | M0A0B1ft |
| \(\dfrac{80}{93}\) implies B1ft | M0A0B1ft |
| \(\dfrac{93}{80} = 1\dfrac{3}{80}\) (incorrect conversion to mixed number) | M1A1B1 |
| \(\dfrac{186}{160} = \dfrac{31}{30}\) (incorrect simplification of fraction) | M1A1B0 |
| \(\dfrac{93}{80} = \dfrac{31}{30}\) (incorrect simplification of fraction) | M1A1B0 |
| \(\dfrac{93}{80} = \dfrac{0.93}{0.8}\) (incorrect simplification of fraction) | M1A1B0 |
| \(\dfrac{186}{16} = \dfrac{93}{8}\) | M0A0B1ft |
| \(\dfrac{1.86}{1.6} = \dfrac{9.3}{8}\) | M1A0B0 |
| \(\dfrac{1.86}{1.6} = \dfrac{186}{16} = \dfrac{93}{8}\) | M1A0B1ft |
| \(\dfrac{1.86}{1.6} = \dfrac{86}{60} = \dfrac{43}{30}\) (simplification does not come from 186 and 16(0)) | M1A0B0 |