Foundation November 2024 Paper 2 Q26
26 Here is a rectangle.
All measurements are in centimetres.
Not drawn accurately
\(AB : BC = 1 : 3\)
Work out the value of the area. [5 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(4x + 1 = 2x + 17\) | M1 | oe equation in terms of \(x\) any letter |
| \(4x - 2x = 17 - 1\) or \(1 - 17 = 2x - 4x\) or \((x =)\ 8\) | M1dep | oe collection of terms |
| Correctly substitutes their 8 into a correct expression for the length or width of the rectangle | M1 | their \(8 \gt 0\) and their \(8 \ne 1\) |
| Correct method for both the length and the width of the rectangle using their 8 | M1dep | their \(8 \gt 0\) and their \(8 \ne 1\) dep on 3rd M |
| 3267 | A1 | SC1 \(12x + 3\) or \(6x + 51\) |
Additional guidance
| The first M1 or SC1 may be awarded for correct work with no answer or incorrect answer, even if this is seen amongst multiple attempts | |
| Trial and improvement to find \((x =)\ 8\) is M2 | |
| Using an incorrect value of \(x\) for 3rd and 4th marks eg when \(x = 10\) \(4 \times 10 + 1 = 41\) and \(41 \times 3 = 123\) or \(12 \times 10 + 3 = 123\) and \(123 \div 3 = 41\) or \(2 \times 10 + 17 = 37\) and \(6 \times 10 + 51 = 111\) | M0M0M1M1dep M0M0M1M1dep M0M0M1M1dep |