Foundation November 2022 Paper 3 Q23
23 Joe, Kim and Lisa each have an amount of money.
Joe has £72
Joe’s amount : Kim’s amount \(= 6 : 5\)
Lisa’s amount is \(1\dfrac{1}{2}\) times Joe’s amount.
Show that, in total, they have less than £250 [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| Alternative method 1 | ||
| \(72 \div 6 \times 5\) or 60 | M1 | oe \(72 \div 6 \times 11\) or 132 implies M1 |
| \(72 \times 1.5\) or 108 | M1 | oe eg \(72 \times 3 \div 2\) \(14 \times 12\) implies M2 |
| 60 and 108 and 240 or \(250 - 60 - 108 = 82\) | A1 | oe eg1 168 and 240 eg2 60 and 108 and 10 eg3 168 and \((250 - 72 =)\) 178 |
| Alternative method 2 | ||
| \(6 \times 1.5\) or 9 | M1 | oe eg1 \(6 \times 3 \div 2\) eg2 \(6 : 5 : 9\) |
| \(72 \div 6 \times (6 + 5 +\) their \(9)\) or \(72 \div 6 \times 5\) and \(72 \div 6 \times\) their 9 | M1dep | oe eg \(12 \times 20\) \(14 \times 12\) implies M2 |
| 9 and 240 or 60 and 108 and 240 or \(250 - 60 - 108 = 82\) | A1 | oe eg1 168 and 240 eg2 60 and 108 and 10 eg3 168 and \((250 - 72 =)\) 178 |
Additional guidance
| Up to M2 may be awarded for correct work, with no or incorrect answer, even if this is seen amongst multiple attempts | |
| In Alt 1 the 2nd mark is not dependent In Alt 2 the 2nd mark is dependent | |
| 240 alone or 240 with no correct method | M0 |
| \(72 \div 6 \times 11 = 132\) and \(132 + 108 = 240\) | M1M1A1 |
| \(1\dfrac{1}{2} \times 72 = 36\) and \(72 + 36 = 108\) and \(72 + 60 + 108 = 240\) | M1M1A1 |
| \(1\dfrac{1}{2} \times 72 = 36\) | M1 |
| \(1\dfrac{1}{2}\) of \(72 = 36\) | M0 |
| \(72 \div 11\) | M0 |