Foundation June 2019 Paper 2 Q17
17 In a bag there are 10p coins, 20p coins and 50p coins.
There are two fewer 20p coins than 10p coins.
There are five more 50p coins than 10p coins.
(a) Complete the table. [1 mark]
| Coin | Number of coins |
|---|---|
| 10p | \(n\) |
| 20p | \(n - 2\) |
| 50p |
(b) Altogether, there are 60 coins.
Work out the total value of the 20p coins. [4 marks]
| Answer | Mark | Comments |
|---|---|---|
| \(n + 5\) or \(5 + n\) | B1 | oe eg \(N - 2 + 7\) |
Additional guidance
| Letters other than \(n\) or \(N\) eg \(x + 5\) | B0 |
| Answer | Mark | Comments |
|---|---|---|
| \(n + n - 2 +\) their \((n + 5)\) or \(3n + 3\) | M1 | condone any letter ft their algebraic expression in (a) |
| \(3n + 3 = 60\) or \((n =)\ 19\) or \((n - 2 =)\ 17\) | M1dep | ft their algebraic expression in (a) correct ft equation with terms on LHS collected 19 10p coins or 17 20p coins or 19, 17, 24 chosen implies M2 |
| (their \(19 - 2) \times 0.2\) or their \(17 \times 0.2\) or 3.4 or (their \(19 - 2) \times 20\) or their \(17 \times 20\) or 340 | M1dep | ft their algebraic expression in (a) 3.4 or 340 implies M3 |
| 3.40 | A1 | condone 3.40p SC2 answer 17 |
Additional guidance
| Allow a restart in this part ie answer £3.40 scores full marks | |
| Working may be seen by the table | |
| Answer 340p | M1M1M1A0 |
| £3.40 with answer eg £17.30 (total of all coins) | M1M1M1A0 |
| Only follow through their algebraic expression from (a) if an expression and / or equation for the total number of coins is used in this part | |
| Award the M mark(s) for a correct ft expression or equation even if not subsequently used | |
| The solution to an equation derived from an incorrect expression in (a) can score the first three marks eg answer in (a) \(n - 5\) then working in (b) \(\quad n + n - 2 + n - 5 = 60 \quad n = [22, 23]\) \(([22, 23] - 2) \times 0.2 = [4, 4.20]\) | M1M1 M1A0 |