Numeracy Foundation June 2019 Unit 2 Q1
1. Geraint went to a petrol station and put petrol in his car.
This was the display on the petrol pump.
Geraint put 30 litres of petrol in his car.
The price of petrol was 127.9 pence per litre.
The cost of the petrol was £38.37.
(a)
The following week the price of petrol was 128.9 pence per litre.
Geraint put 40 litres of petrol in his car.
What was the cost of the petrol?
Give your answer in pounds (£). [3]
Cost of 40 litres of petrol was £ ……………
(b)
The display below shows the cost of 35 litres of petrol.
Calculate the price per litre of petrol.
Give your answer in pence. [3]
| This Sale £ | 44.38 |
| Litres | 35.00 |
| Pence per litre | …………… |
| Scheme | Marks | Comments |
|---|---|---|
| 128.9 (pence) × 40 (litres) = (£)51.56 | M1 A2 | Allow incorrect place value Allow £51.56p A1 for sight of digits 5156 with incorrect place value or units (e.g. £5156 or 5156p or 51.56p) Unsupported sight of digits 5156 implies M1A1 ISW Treat use of 127.9 as MR (-1 from A marks only) |
Alternative
Alternative method (printed in italics in the mark scheme)
| Scheme | Marks | Comments |
|---|---|---|
| (128.9 (pence) ÷ 100 =) (£)1.289 | B1 | B0 for (£)1.28 or (£)1.29 |
| (£)1.289 × 40 (litres) | M1 | Allow use of (£)1.28 × 40 (litres) or (£)1.29 × 40 (litres) |
| (£)51.56 | A1 | Note: (£)1.28 × 40 (litres) = (£)51.2(0) (£)1.29 × 40 (litres) = (£)51.6(0) Unsupported (£)51.2(0) or (£)51.6(0) implies B0M1A1 ISW |
| Scheme | Marks | Comments |
|---|---|---|
| 4438 ÷ 35 126.8 (pence) | M1 A2 | Allow 44·38 ÷ 35 A1 for sight of the digits 1268 with incorrect place value or units (e.g.£126.8 or (£)1.268 or (£)1.27 or 127(p)) Unsupported sight of digits 1268 implies M1A1 ISW |