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Intermediate November 2018 Unit 2 Q12

WJECIntermediateCurrent spec6 marksDrawing & Using GraphsSolving Quadratics

12. The table below shows some of the values of \(y = x^2 + 4x - 1\) for values of \(x\) from –5 to 2.

\(x\)–5–4–3–2–1012
\(y = x^2 + 4x - 1\)4–1–4–4–14
(a) Complete the table by finding the value of \(y\) for \(x = -2\) and for \(x = 2\). [2]
(b) On the graph paper below, draw the graph of \(y = x^2 + 4x - 1\) for values of \(x\) from –5 to 2. [2]
(c) Draw the line \(y = 2\) on the graph paper.
Write down the values of \(x\) where the line \(y = 2\) cuts the curve \(y = x^2 + 4x - 1\). [2]

Values of \(x\) are   ………………………   and   ………………………

Graph paper grid with x from −5 to 2 and y from −6 to 12