Intermediate November 2018 Unit 2 Q6
6.
(a) Solve \(\dfrac{m}{2} = 4{\cdot}8\). [1]
(b) Factorise the following.
(i) \(6x - 15\) [1]
(ii) \(y^2 + 4y\) [1]
(c) The nth term of a sequence is given by \(3n - 20\).
(i) What is the value of the 6th term? [1]
(ii) Consider the following statement.
‘There are no odd numbers greater than 50 in this sequence.’
Show that this statement is incorrect. [1]
‘There are no odd numbers greater than 50 in this sequence.’
Show that this statement is incorrect. [1]
| Scheme | Marks | Comments |
|---|---|---|
| (m = ) 9·6 | B1 | Mark final answer. Allow embedded answer. B1 for 9·6/2 or 9·6/2 = 4·8 with no further work. B0 for 9·6/2 followed by ‘m ≠ 9·6’. |
| Scheme | Marks | Comments |
|---|---|---|
| (i) 3(2x – 5) | B1 | Allow 3 × (2x – 5) |
| (ii) y(y + 4) | B1 | Allow y × (y + 4) |
| Scheme | Marks | Comments |
|---|---|---|
| (i) −2 | B1 | B0 for −2n. Mark final answer. |
| (ii) Example given, e.g. 3 × 25 – 20 = 55 | B1 | Candidates must show a calculation or link a term with its correct value e.g. ‘25th term is 55’. If they list the terms, then the list must be accurate and start at −2 (6th term) or one of the previous terms. |