Foundation November 2018 Unit 2 Q13
13. \(ABC\) is an isosceles triangle and \(ABP\) is a straight line.
\(AC = BC\) and \(A\hat{C}B = 76^\circ\).

Diagram not drawn to scale
Calculate the size of \(C\hat{B}P\).
You must show all your working. [3]
| Scheme | Marks | Comments |
|---|---|---|
| (ABC or BAC =) \(\dfrac{180 - 76}{2}\) | M1 | Angles may be shown on the diagram. |
| = 52(°) | A1 | |
| (CBP = 180 – 52 =) or (CBP = 76 + 52 =) 128(°) | B1 | F.T. 'their derived, stated or shown 52' BUT not 76. |