Percentages: WJEC GCSE Numeracy Foundation November 2022 Unit 2 Q3

Numeracy Foundation November 2022 Unit 2 Q3

WJECFoundationCurrent spec7 marksPercentages Pie Charts

(a)

The Royal National Lifeboat Institution (RNLI) bought a new lifeboat.
The lifeboat was funded as follows:

The new lifeboat cost £2.2 million.

How much of the cost of this lifeboat was funded from government sources?
Write your answer in figures only. [3]

£ ……………………

(b)

1800 medals were awarded to RNLI crew members in recent years.
The distribution of the medals is shown accurately in the pie chart below.

(i) What fraction of the medals awarded were bronze?
Circle your answer. [1]

\(\dfrac{135}{360}\) \(\dfrac{245}{360}\) \(\dfrac{65}{360}\) \(\dfrac{115}{360}\) \(\dfrac{75}{360}\)

(ii) How many gold medals were awarded?
You must show all your working. [3]

Mark scheme (a)

Scheme	Marks	Comments
Use of 1 million as 1 000 000	B1	May be seen at any stage of working or implied by a correct answer Accept from sight of 2.2 million written as 2 200 000 Allow as implied from one of the following: sight of an appropriate stage of working, e.g. 1% as 22 000 or 10% as 220 000 or 50% as 1 100 000 an answer of 40 000 provided not from 0.2 × 2 million
0.02 × 2.2 (× 1 000 000) or (1 000 000 ×) 2.2 ÷ 50 or equivalent	M1	The method must be for the intention of finding 2% of 2.2 million, not any other percentage May be implied, from a full method, from sight of 0.02 × ‘digits 22 with place value error’ when working not shown, only non-zero digits of 44 in their answers Award M0 for 1.02 × 2.2 or 0.98 × 2.2 or 0.2 × 2.2
(£) 44 000 or (£) 44,000	A1	CAO. Answer space takes precedence Do not accept (£)0.044 (million) or 44.000 (A0) unless 44000 seen in working (A1)

Mark scheme (b)

Scheme	Marks	Comments
(i) \(\dfrac{115}{360}\)	B1
(ii) Gold 20° ±2°	B1	Check the diagram
1800 × \(\dfrac{20\ (\pm 2)}{360}\) or 5 × (20 (±2)) or equivalent	M1	Also implies previous B1 FT for any value used for ‘20’ provided ≠180° and < 360°) for M1 only (including use of 160°)
100 (gold medals)	A1	A correct answer from using 20°±2° in the inclusive range 90 to 110 (gold medals), not from premature approximation (20/360 = 0.05, then 0.05 × 1800 = 90 B1 M1 A0)