Numeracy Intermediate November 2019 Unit 1 Q11
11.
(a) Gwilym is stacking 6 boxes in his garage.
The height of his garage is 2·5 m, correct to the nearest 10 cm.
5 of Gwilym’s boxes each have a height of 40 cm, correct to the nearest 10 cm.
The other box has a height of 55 cm, correct to the nearest 5 cm.
Calculate the maximum possible gap between the stack of 6 boxes and the garage ceiling. [4]
(b) Inside one of the boxes is an old clock.
Gwilym takes the clock to be valued.
It is valued at £56.
The clock has decreased in value by 30% from last year.
Gwilym takes the clock to be valued.
It is valued at £56.
The clock has decreased in value by 30% from last year.
Calculate how much the clock was worth last year. [2]
| Scheme | Marks | Comments |
|---|---|---|
| Sight, for the garage, of 2.55(m) or 255(cm) | B1 | Provided not from incorrect working (i.e. 40 × 5 + 55 = 255 is awarded B0) |
| Sight ,for the boxes, of 35(cm) and 52.5(cm) | B1 | |
| 255 – (5 × 35 + 52.5) or 255 – 175 – 52.5 or 255 – 227.5 or equivalent | M1 | FT provided 250 <‘their 255’≤ 260 or 2.5<‘their 2.55’≤ 2.6 and provided 30 ≤ ‘their 35’ <40 and 50 ≤ ‘their 52.5’ <55 FT from consistent place value error for a similar range for ‘their bounds’ |
| 27.5 (cm) or 0.275 (m) | A1 | CAO. ISW |
| Scheme | Marks | Comments |
|---|---|---|
| 56 ÷ 0.7 or equivalent | M1 | |
| (£) 80 | A1 |