Numeracy Higher June 2023 Unit 1 Q9
9.
One of their cocktail glasses is shown below.
A hollow hemisphere forms the part of the glass which can hold the drink.

Diagram not drawn to scale
Before each hemisphere is attached to a stem, the surface area on the outside of each hemisphere is given a decorative coating.
The volume of each hemisphere is \(\dfrac{128\pi}{3}\) cm3.
Calculate the surface area that is given a decorative coating.
Give your answer in terms of π in its simplest form. [6]
These glasses are mathematically similar.

Diagram not drawn to scale
The ratio of the volume of the smaller glass to the volume of the larger glass is 8 : 27.
The height of the larger glass is 18 cm.
Calculate the height of the smaller glass. [3]
From the formula list: Volume of sphere \(= \dfrac{4}{3}\pi r^3\); Surface area of sphere \(= 4\pi r^2\)
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{2}{3}\) × π × radius3 = \(\dfrac{128\pi}{3}\) or equivalent | M1 | |
| radius3 = \(\dfrac{128\pi \times 3}{2 \times \pi \times 3}\) or equivalent OR radius = \(\sqrt[3]{\dfrac{128\pi \times 3}{2 \times \pi \times 3}}\) or equivalent | M1 | For isolating radius3 FT if the volume of a sphere used for a possible M1A1 only |
| (radius =) 4 (cm) | A2 | CAO A1 for radius3 = 64 or (radius =) \(\sqrt[3]{64}\) OR A1 for radius3 = 32 or (radius =) \(\sqrt[3]{32}\) if the volume of a sphere used |
| (Surface area =) 2 × π × 42 | M1 | FT ‘their 4’ provided an attempt made to use the formula for the volume of a sphere to calculate the radius |
| = 32π (cm2) | A1 | Accept 3200π mm2 or 0.0032π m2 If ‘their radius = \(\sqrt[3]{32}\)’ then their SA will be 213/3 π If final M0A0, award SC1 for 4 × π × ‘their r2’ evaluated correctly provided an attempt made to use the formula for the volume of a sphere to calculate the radius |
| Scheme | Marks | Comments |
|---|---|---|
| \(\sqrt[3]{8} : \sqrt[3]{27}\) or \(\sqrt[3]{8 \div 27}\) or \(\sqrt[3]{27 \div 8}\) ( = 2 : 3) (= 2/3) (= 3/2) | B1 | May be implied in further working |
| (Height =) 18 × \(\dfrac{2}{3}\) or 18 ÷ \(\dfrac{3}{2}\) or equivalent | M1 | Implies previous B1 provided not from incorrect working FT ‘their 2/3’ or ‘their 3/2’ provided first B1 awarded |
| = 12 (cm) | A1 | CAO Note: 27 ÷ 18 = 1.5 followed by either 18 ÷ 1.5 = 12 or 8 × 1.5 = 12 is awarded B0M0A0 |