Numeracy Foundation November 2022 Unit 1 Q10
10. Malik has some cherry trees.
Malik makes cherry jam using some of the fruit from his trees.
He makes and sells 200 jars of cherry jam.
It costs him £94 for all the ingredients to make the jam.
Malik pays 23p for each jam jar he uses.
He sells each jar of jam for £1.60.
Calculate the profit Malik makes from selling his 200 jars of jam. [5]
| Scheme | Marks | Comments |
|---|---|---|
| Method 1 for 200 jars (Cost of 200 jars) 200 × (0.)23 OR (Sales of 200 jars of jam) 200 × 1(.)60 | M1 | |
| (Cost of 200 jars) 4600(p) or (£)46 (Sales of 200 jars of jam) 32000(p) or (£)320 | A1 A1 | |
| (Cost 200 jars + jam) (£94 +£46=) (£)140 or 14000(p) | B1 | FT £94 + ‘their derived £46’ |
| (Profit £320 - £140 =) 18000(p) or (£)180 | B1 | If units are given they must be correct FT ‘their derived £320’ – ‘their derived £140’ |
10. Method 2 for 200 jars
| Scheme | Marks | Comments |
|---|---|---|
| (Cost of jam for 200 jars) 200 × (1(.)60 – 0(.)23) | M2 | M1 for 1(.)60 – 0(.)23 or (£)1.37 or 137(p) |
| (=) £) 274 or 27400(p) | A2 | A1 for 200 × 1(.)37 |
| (Profit £274 - £94 =)18000(p) or (£)180 | B1 | If units are given they must be correct FT ‘their derived £274’ – £94 |
10. Method for 1 jar
| Scheme | Marks | Comments |
|---|---|---|
| (Cost of ingredients for 1 jar of jam) 94(00) ÷ 200 | M1 | |
| 47(p) or (£)0.47 | A1 | |
| (Cost of jam and jar) (23p + 47p =) 70(p) or (£)0.7(0) | B1 | FT ‘their derived 47p’ + 23p |
| (Profit for 1 jar of jam £1.60 – 70p =) 90(p) or(£)0.9(0) | B1 | FT £1.60 - ‘their derived 70p’ May be seen or implied in later working |
| (Profit for 200 jars of jam) 18000(p) or (£)180 | B1 | If units are given they must be correct FT ‘their derived 90p’ |