Intermediate November 2021 Unit 2 Q1
1.
(a) Solve \(7x - 3 = 11\). [2]
(b) Find the value of \(3f + 2g\) when \(f = 5{\cdot}8\) and \(g = -3{\cdot}7\). [2]
| Scheme | Marks | Comments |
|---|---|---|
| 7x =14 | B1 | |
| x = 2 | B1 | FT from 7x = k. Accept x = k/7 (but, if on FT k is a multiple of 7, final answer must be given as a whole number.) B1B0 for ‘x = 14/7’ An evaluated FT for k ÷ 7 must be rounded or truncated to at least 2dp. e.g. 7x = 8 (B0) followed by, x = 8 ÷ 7 (B0) x = 8/7 (B1), x = 11/7 (B1), x = 1·14 (B1), x = 1·1 (B0) Mark final answer. Allow 2 marks for embedded answer BUT only 1 mark if contradicted by x ≠ 2. |
| Scheme | Marks | Comments |
|---|---|---|
| 10 | B2 | C.A.O. B1 for sight of 17·4 OR −7·4 Do not accept 17·4f nor −7·4g Do not treat the use of 3·7 for −3·7 as a misread. |