Foundation June 2022 Unit 1 Q18
18. A rectangle and a trapezium are shown below.
Diagrams not drawn to scale
The area of the rectangle = 48 m2.
The width of the rectangle is represented by \(x\).
The height of the trapezium is twice the width of the rectangle.
Calculate the area of the trapezium.
You must show all your working. [4]
From the formula list: Area of trapezium \(= \dfrac{1}{2}(a+b)h\)
| Scheme | Marks | Comments |
|---|---|---|
| (Area of rectangle) 48 = 8 × \(x\) | M1 | Lengths may be shown on the diagrams. |
| (width of rectangle, \(x\) = 48/8 =) 6 (m) | A1 | Allow an embedded 6 e.g. 8 × 6 = 48 for M1A1. |
| (Area of trapezium =) \(\dfrac{(5 + 9) \times (6 \times 2)}{2}\) or equivalent | M1 | Sight of 12(m) implies the previous M1A1. FT ‘their stated \(x\)’ × 2. Allow M1 for correct intent seen. e.g. 5 + 9 × 12 ÷ 2 |
| = 84 (m2) | A1 |