Numeracy Intermediate November 2024 Unit 2 Q9
9.
The base of a flagpole is fixed to horizontal ground.
It is held vertically by a straight rod of length 3·8 m.
The rod is fixed to the ground and to a point 1·5 m from the top of the flagpole.
The flagpole and the rod are shown in the diagram below.

Diagram not drawn to scale
Calculate the total height of the flagpole.
Give your answer correct to the nearest centimetre. [4]
Mathematically similar large, medium and small flags are made.

Diagrams not drawn to scale
Length of the medium flag is …………… cm
Height of the small flag is …………… cm
| Scheme | Marks | Comments |
|---|---|---|
| (Length of the flagpole below the rod =) 3.8 × sin 55° or 3.8 × cos (90° – 55°) or 380 × sin 55° or 380 × cos (90° – 55°) | M2 | Or alternative full method M1 for correct working without isolating ‘length’ \(\sin 55^\circ\) = \(\dfrac{\text{length}}{3.8}\) or \(\cos (90^\circ - 55^\circ)\) = \(\dfrac{\text{length}}{3.8}\) or \(\sin 55^\circ\) = \(\dfrac{\text{length}}{380}\) or \(\cos (90^\circ - 55^\circ)\) = \(\dfrac{\text{length}}{380}\) |
| 3.11(2…m) or 311(.2.. cm) | A1 | Allow 3.1 (m) or 310 (cm) |
| (Total length 1.5 + 3.11 =) 4.61 (m) or 461 (cm) | A1 | Must be to the nearest cm FT provided at least M1 previously awarded, i.e. for 1.5 + ‘their 3(.)11’ correctly evaluated, to nearest cm, and ‘their 3.11’ is to at least 2 decimal places If units are given they must be correct |
| Scheme | Marks | Comments |
|---|---|---|
| (i) 120 × 64 ÷ 80 or 64 × 1.5 or 120 × 0.8 or 120 ÷ 1.25 or 64 ÷ \(\dfrac{2}{3}\) or equivalent | M1 | |
| 96 (cm) | A1 | Answer space takes precedence |
| (ii) 75 × 80 ÷ 120 or 75 ÷ 1.5 or 75 × \(\dfrac{2}{3}\) or 80 ÷ 1.6 or 80 × 0.625 or 64 × 75 ÷ 96 or equivalent | M1 | FT from (b)(i) 64 × 75 ÷ ‘their 96’ or equivalent |
| 50 (cm) | A1 | Answer space takes precedence |