Question Bank › GCSE Shape & Space › Basic Trigonometry
Basic Trigonometry Topic Angles (Including Parallel Lines) (19) Angles in Polygons (12) Constructions (11) Circle Theorems (5) Volume & Surface Area (13) Prisms (8) 2D Area & Perimeter (21) Circles & Sectors (16) Similar Shapes (14) Transformations of Shapes (15) Vectors (7) Basic Trigonometry (10) Advanced Trigonometry (9) Pythagoras (12) Exact Trig & Graphs (6) Plans, Elevations & Nets (6) Current PowerPoint version
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Foundation June 2025 Paper 2 Q26 26 \(ABC\) is a right-angled triangle.
Calculate the value of \(x\). Give your answer correct to 1 decimal place. (2)
Mark scheme
Mark scheme Answer Mark Mark scheme 60.3 M1 for a correct trig statement, eg \(\tan x = \dfrac{7}{4}\) A1 60.2 to 60.42
Additional guidance Other methods are possible but only award this mark at the point of an equation with \(x\) as the only unknown
Higher June 2025 Paper 2 Q7 7 \(ABC\) is a right-angled triangle.
Calculate the value of \(x\). Give your answer correct to 1 decimal place. (2)
Mark scheme
Mark scheme Answer Mark Mark scheme 60.3 M1 for a correct trig statement, eg \(\tan x = \frac{7}{4}\) A1 60.2 to 60.42
Additional guidance Other methods are possible but only award this mark at the point of an equation with \(x\) as the only unknown
Foundation November 2024 Paper 3 Q24 24 \(ABC\) is a right-angled triangle.
Calculate the length of \(AB\). Give your answer correct to 1 decimal place. (2)
Mark scheme
Mark scheme Answer Mark Mark scheme 14.3 M1 for a correct statement for \(AB\) using trigonometry, eg \(\tan 62 = \dfrac{AB}{7.6}\) or \((AB =)\ 7.6 \times \tan 62\) A1 answer in the range 14.28 to 14.3
Additional guidance If an answer is given in the range in working and then rounded incorrectly award full marks
Higher November 2024 Paper 3 Q8 8 \(ABC\) is a right-angled triangle.
Calculate the length of \(AB\). Give your answer correct to 1 decimal place. (2)
Mark scheme
Mark scheme Answer Mark Mark scheme 14.3 M1 for a correct statement for \(AB\) using trigonometry, eg \(\tan 62 = \dfrac{AB}{7.6}\) or \((AB =)\ 7.6 \times \tan 62\) A1 answer in the range 14.28 to 14.3
Additional guidance If an answer is given in the range in working and then rounded incorrectly award full marks
Foundation June 2025 Paper 2 Q26 26
Not drawn accurately
Use trigonometry to work out the value of \(x\).
You must show your working. [3 marks]
Mark scheme
Mark scheme Answer Mark Comments Alternative method 1: uses or states tan tan stated or used M1 implied by [0.726, 0.73] or [1.376, 1.4] \(\tan 36 = \dfrac{x}{4}\) or \(4 \times \tan 36\) or \(\tan 54 = \dfrac{4}{x}\) or \(\dfrac{4}{\tan 54}\) M1dep oe accept [0.726, 0.73] for tan 36 accept [1.376, 1.4] for tan 54 [2.9, 2.91] with M2 awarded A1 accept 3 with M2 awarded Alternative method 2: works out hypotenuse first (hypotenuse \(=\)) \(\dfrac{4}{\sin 54}\) or \(\dfrac{4}{\cos 36}\) or 4.9(…) M1 oe accept [0.8, 0.81] for sin 54 or cos 36 \(\sqrt{(\text{their } 4.9(\ldots))^2 - 4^2}\) or \(\sqrt{[8, 8.45]}\) or their 4.9(…) \(\times \sin 36\) or their 4.9(…) \(\times \cos 54\) M1dep oe [2.9, 2.91] with M2 awarded A1 accept 3 with M2 awarded
Additional guidance Alt 1 SOHCAHTOA with TOA selected (eg circled) M1 [2.9, 2.91] with no working M0M0A0 [2.9, 2.91] from accurate/scale drawing only M0M0A0
Foundation November 2024 Paper 2 Q22 22 Use trigonometry to work out the value of \(x\). [3 marks]
Not drawn accurately
Mark scheme
Mark scheme Answer Mark Comments Alternative method 1 – using sin 40 sin chosen or used M1 \(21 \times \sin 40\) M1dep accept \(21 \times [0.64, 0.643]\) [13.49, 13.5] A1 Alternative method 2 – using cos 50 \(\cos (90 - 40)\) M1 \(21 \times \cos (90 - 40)\) M1dep oe accept \(21 \times [0.64, 0.643]\) [13.49, 13.5] A1 Alternative method 3 – finds base then uses Pythagoras \(21^2 - (21 \sin (90 - 40))^2\) M1 oe complete method except square root \(\sqrt{21^2 - (21 \sin (90 - 40))^2}\) or \(\sqrt{[182.2, 182.22]}\) M1dep oe [13.49, 13.5] A1
Additional guidance Check diagram for working Allow correct use of sine rule to indicate sin Ignore rounding or truncating after the correct answer is seen eg answer 14 after 13.5 seen M1M1A1\(\sin 40 \times 21\) M2 sin may be indicated by eg circling S in SOH CAH TOA Do not accept answers from full sized or scale drawing sin 50 used (unless using Alt 3) M0
Foundation June 2024 Paper 2 Q19 19
Not drawn accurately
Use trigonometry to work out the value of \(x\). [3 marks]
Mark scheme
Mark scheme Answer Mark Comments Alternative method 1 \(\sin\) chosen or used M1 \(31 \times \sin 24\) M1dep accept \(31 \times [0.4, 0.41]\) [12.6, 12.61] A1 accept 13 if M2 awarded Alternative method 2 \(\cos (90 - 24)\) M1 \(31 \times \cos (90 - 24)\) M1dep accept \(31 \times [0.4, 0.41]\) [12.6, 12.61] A1 accept 13 if M2 awarded
Additional guidance Check diagram for working Allow correct use of sine rule to indicate \(\sin 24\) Ignore rounding or truncating after the correct answer is seen \(\sin 24 \times 31\) M2 Do not accept answers from full sized or scale drawing \(\sin\) may be indicated by eg circling S in SOH CAH TOA
Foundation November 2023 Paper 3 Q23 23 Use trigonometry to work out the size of angle \(w\). [3 marks]
Not drawn accurately
Mark scheme
Mark scheme Answer Mark Comments Alternative method 1 cos chosen or used M1 \(\cos w = \dfrac{6.7}{8.3}\) or \(\cos^{-1} \dfrac{6.7}{8.3}\) M1dep any letter or symbol for \(w\) accept 0.807(…) or 0.81 for \(\dfrac{6.7}{8.3}\) [35.9, 36.2] A1 Alternative method 2 \(\sin x = \dfrac{6.7}{8.3}\) or \(\sin^{-1} \dfrac{6.7}{8.3}\) or [53.8, 54.1] M1 any letter or symbol other than \(w\) accept 0.807(…) or 0.81 for \(\dfrac{6.7}{8.3}\) \(90 -\) their [53.8, 54.1] M1dep [35.9, 36.2] A1 Alternative method 3 \(\sqrt{8.3^2 - 6.7^2}\) or \(\sqrt{68.89 - 44.89}\) or \(\sqrt{24}\) or \(2\sqrt{6}\) or [4.89, 4.9]and \(\sin^{-1} \dfrac{\text{their } [4.89, 4.9]}{8.3}\) or \(\tan^{-1} \dfrac{\text{their } [4.89, 4.9]}{6.7}\) M2 full method to work out the missing length and use it correctly to work out the value of \(w\) any letter or symbol for \(w\) [35.9, 36.2] A1
Additional guidance Use of sine rule follows Alt method 2 \(\sin w = \dfrac{6.7}{8.3}\) without \(\sin^{-1} \dfrac{6.7}{8.3}\) or [53.8, 54.1] M0 \(\cos w = 0.807\) M1M1 \(\cos^{-1} w = \dfrac{6.7}{8.3}\) or \(\cos = \dfrac{6.7}{8.3}\) unless recovered M1M0
Foundation June 2017 Paper 2 Q29 29 Use trigonometry to work out the length \(x\).
Not drawn accurately
[2 marks]
Mark scheme
Mark scheme Answer Mark Comments \(\sin 72 = \dfrac{x}{8}\) or \(8 \times \sin 72\) or \(\cos(90 - 72) = \dfrac{x}{8}\) or \(8 \times \cos(90 - 72)\) or \(\dfrac{x}{\sin 72} = \dfrac{8}{\sin 90}\) or \(\dfrac{\sin 72}{x} = \dfrac{\sin 90}{8}\) M1 oe eg \(8\cos 72\) or 2.47… or 2.5and \(\sqrt{8^2 - (8\cos 72)^2}\) [7.6, 7.61] A1
Additional guidance If trigonometry and Pythagoras are used it must be a fully correct method that would lead to the correct value of \(x\) Accept \(\sin 72 \times 8\) M1 Accept opp or o for \(x\) \(\;\) eg \(\;\sin 72 = \dfrac{\text{opp}}{8}\) M1 \(\sin = \dfrac{x}{8}\) or \(\sin\theta = \dfrac{x}{8}\) (unless recovered) M0 Answer coming from scale drawing M0A0 Answer in range seen followed by 7 or 8 M1A1
Higher June 2017 Paper 2 Q7 7 Use trigonometry to work out the length \(x\).
Not drawn accurately
[2 marks]
Mark scheme
Mark scheme Answer Mark Comments \(\sin 72 = \dfrac{x}{8}\) or \(8 \times \sin 72\) or \(\cos (90 - 72) = \dfrac{x}{8}\) or \(8 \times \cos (90 - 72)\) or \(\dfrac{x}{\sin 72} = \dfrac{8}{\sin 90}\) or \(\dfrac{\sin 72}{x} = \dfrac{\sin 90}{8}\) M1 oe eg \(8 \cos 72\) or 2.47… or 2.5and \(\sqrt{8^2 - (8\cos 72)^2}\) [7.6, 7.61] A1
Additional guidance If trigonometry and Pythagoras are used it must be a fully correct method that would lead to the correct value of \(x\) Accept \(\sin 72 \times 8\) M1 Accept opp or o for \(x\) \(\;\) eg \(\sin 72 = \dfrac{\text{opp}}{8}\) M1 \(\sin = \dfrac{x}{8}\) or \(\sin \theta = \dfrac{x}{8}\) (unless recovered) M0 Answer coming from scale drawing M0A0 Answer in range seen followed by 7 or 8 M1A1
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