Foundation November 2019 Paper 1 Q14
14. The organiser of a teachers’ conference provided a buffet lunch made by a catering service.
The catering service made a total of 560 cups of tea and coffee.
These were served in the ratio 5 : 3 respectively.
The catering service billed the conference organiser £1 for each cup of tea and £1.50 for each cup of coffee served.
How much was the total bill for the tea and coffee? [4]
The buffet food was placed on 3 large tables, one for meat, one for vegetarian and one for vegan dishes.
Teachers chose their food from one of these tables.
The numbers of teachers per minute who chose food from the table of meat dishes and the table of vegetarian dishes is shown below.
| Table | Meat | Vegetarian | Vegan |
|---|---|---|---|
| Number of teachers per minute | 8 | 4 |
After 5 minutes, 95 teachers had chosen their food.
How many teachers per minute chose their food from the table of vegan dishes?
You may assume that the teachers chose their food at a constant rate. [3]
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{560}{5+3} \times 5 + \dfrac{560}{5+3} \times 3 \times 1.5\) oe or \(560 + \dfrac{560}{5+3} \times 3 \times 0.5\) | M3 | May be in steps; M2 for sight of \(\dfrac{560}{5+3} \times 5\ (\times 1)\) (= 70 × 5 = 350) or \(\dfrac{560}{5+3} \times 3 \times 1.5\) (= 210 × 1.5 = 315) or \(\dfrac{560}{5+3} \times 3 \times 0.5\) (= 210 × 0.5 = 105) OR for 560 ÷ (5 + 3) (= 560 ÷ 8 = 70) and 5 + 3 × 1.5(0) (5 + 4.50 = 9.50) or M1 for 560 ÷ (5 + 3) (= 560 ÷ 8 = 70) |
| (£) 665 | A1 | CAO |
| Scheme | Marks | Comments |
|---|---|---|
| \(\dfrac{95}{5} - 8 - 4\) or \(\dfrac{95 - (8 \times 5 + 4 \times 5)}{5}\) | M2 | M1 for sight of \(\dfrac{95}{5}\) (= 19) or for 95 − (8 × 5 + 4 × 5) (= 95 – 60 = 35) |
| 7 | A1 | |
| (7) |