Higher November 2020 Paper 1 Q16
16. A tennis club has 240 members.
They each played a senior, main or junior event in one of three competitions, A, B or C.
Of the club members:
- 110 played in A,
- 30 played in a junior event,
- 25 played in the senior event in B,
- no junior played in C,
- 40 of those who played in C were in the main event.
The number of members who played in a senior event was 150% more than those who played in a junior event.
The ratio of members who played in B and C was B : C = 6 : 7.
The probability that a member played in the junior event in A was 0·1.
A member is selected at random from the club.
Use the table to help you to find the probability that this member played in a Main event or played in B but not both.
You must show all your working. [6]
| Senior | Main | Junior | Totals | |
|---|---|---|---|---|
| A | ||||
| B | ||||
| C | ||||
| Totals |
| Scheme | Marks | Comments | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| B3 | Method 1: Using 135, 60, 29 B1 for the given 240, 110, 30, 25, 0, 40 (shaded) correctly placed; allow e.g. an X in the 0 cell B1 for the 75, 135 and 60 correctly placed; B1 for 24, 6, 29 correctly placed or Method 2: Using 25, 40, 6, 66 B1 for the given 240, 110, 30, 25, 0, 40 (shaded) correctly placed; allow e.g. an X in the 0 cell B1 for the 75, 60, 70, 30 and 20 correctly placed; B1 for 24, 66, 6 correctly placed May be probabilities or frequencies; If values not in table then they must be clearly identified | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
| \(\dfrac{135+60-29\times2}{240}\) or \(\dfrac{25+6+66+40}{240}\) oe | M2 | FT ‘their 135, 60, 29’ or ‘their 6, 66’ for M1 or M2 providing they are non-zero M1 for sight of either \(\dfrac{135+60}{240}\left(=\dfrac{13}{16}\right)\) oe, \(\dfrac{25+6+66+40+2\times29}{240}\left(=\dfrac{13}{16}\right)\) oe or sight of 137 | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
| \(\dfrac{137}{240}\) oe, CAO | A1 | If B2 M2 allow SC1 for an answer of \(\dfrac{163}{240}\) (uses 0.1 × 110)
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| (6) |