Higher June 2024 Paper 2 Q11
11. Use:
\[\text{Pressure} = \frac{\text{Force}\,(\text{N})}{\text{Area}\,(\text{cm}^2)}\]A cylindrical fish tank stands on horizontal ground.
The base of the fish tank has a radius of 24 cm.
All the base of the fish tank is in contact with the ground.
The fish tank exerts a pressure of 0·97 N/cm2 on the ground.
What force is exerted on the ground by the fish tank? [4]
| Scheme | Marks | Comments |
|---|---|---|
| (Force =) \(0.97\times\pi\times24^2 = \) \(0.97\times1809.557\) \(0.97 = \text{Force}/(3619.11..)\) gains the M1 (Force =) \(0.97\times3619.11..\) | M3 | May be seen in stages M2 for \(0.97 = \dfrac{\text{Force}}{\pi\times24^2}\) If not M2, award M1 for one of the following:
|
| Answers in the range 1754 to 1756 | A1 | CAO Award A0 if the answer is given as a multiple of \(\pi\) |
| (4) |
Corrected by Westie's Workshop
- The board's mark scheme printed “0.97 1809.557”. Changed to “0.97 × 1809.557” because the multiplication sign between 0.97 and 1809.557 (which is π × 24²) was missing.
Original: see the board's mark scheme PDF (link above).