Foundation June 2025 Paper 1 Q18EduqasFoundationCurrent spec4 marksLinear Graphs & GradientsSubstitution18. The table below shows some of the values of \(y = 3x + 2\) for values of \(x\) from –2 to 3.\(x\)\(-2\)\(-1\)\(0\)\(1\)\(2\)\(3\)\(y = 3x + 2\)\(-1\)\(2\)\(8\)(a) Complete the table by finding the values of \(y\) for \(x = -2\), \(x = 1\) and \(x = 3\). [2](b) On the graph paper below, draw the graph of \(y = 3x + 2\) for values of \(x\) from –2 to 3. [2]Mark scheme (a)Mark scheme (b)Mark scheme (a)SchemeMarksComments\(-4\) \(5\) \(11\)B2B2 for all 3 values.B1 for 2 correct values.Table takes precedence if conflicting values given.Mark scheme (b)SchemeMarksCommentsA correct line drawn from (–2, –4) to (3, 11).B2B1 for either:the correct line drawn but not over the full domainfor 5 points (FT) plotted correctly and up to 1 incorrect.(4)