S2 January 2008 Q6
6. The probability that a sunflower plant grows over 1.5 metres high is 0.25. A random sample of 40 sunflower plants is taken and each sunflower plant is measured and its height recorded.
| Scheme | Marks |
|---|---|
| (i) Let \(X\) represent the number of sunflower plants more than 1.5m high \(X \sim \mathrm{Po}(10)\) \(\mu = 10\) | B1 |
| \(\mathrm{P}(8 \leqslant X \leqslant 13) = \mathrm{P}(X \leqslant 13) - \mathrm{P}(X \leqslant 7)\) \(= 0.8645 - 0.2202\) | M1 |
| \(= 0.6443\) awrt 0.644 | A1 |
| (ii) \(X \sim \mathrm{N}(10, 7.5)\) | B1 |
| \(\mathrm{P}(7.5 \leqslant X \leqslant 13.5) = \mathrm{P}\left(\dfrac{7.5 - 10}{\sqrt{7.5}} \leqslant X \leqslant \dfrac{13.5 - 10}{\sqrt{7.5}}\right)\) | M1 M1 A1 A1 |
| \(= \mathrm{P}(-0.913 \leqslant X \leqslant 1.278)\) \(= 0.8997 - (1 - 0.8186)\) | M1 |
| \(= 0.7183\) awrt 0.718 or 0.719 | A1 |
| (10) |
Notes
(i) B1 mean = 10 May be implied in (i) or (ii)
M1 Attempting to find \(\mathrm{P}(X \leqslant 13) - \mathrm{P}(X \leqslant 7)\)
A1 awrt 0.644
(ii) B1 \(\sigma^2 = 7.5\) May be implied by being correct in standardised formula
M1 using 7.5 or 8.5 or 12.5 or 13.5.
M1 standardising using 7.5 or 8 or 8.5 or 12.5 or 13 or 13.5 and their mean and standard deviation.
A1 award for either \(\dfrac{7.5 - 10}{\sqrt{7.5}}\) or awrt \(-0.91\)
A1 award for either \(\dfrac{13.5 - 10}{\sqrt{7.5}}\) or awrt 1.28
M1 Finding the correct area. Following on from their 7.5 and 13.5. Need to do a Prob >0.5 – prob <0.5 or prob <0.5 + prob< 0.5
A1 awrt 0.718 or 0.719 only. Dependent on them getting all three method marks.
No working but correct answer will gain all the marks
| Scheme | Marks |
|---|---|
| Normal approx /not Poisson | B1 |
| since (\(n\) is large) and \(p\) close to half. or (\(np = 10\) \(npq = 7.5\)) mean \(\ne\) variance or \(np\) (= 10) and \(nq\) (= 30) both >5. or exact binomial = 0.7148 | B1dep |
| (2) | |
| (12 marks) |
Notes
first B1 normal
second B1
\(p\) close to half,
or mean \(\ne\) variance
or \(np\) and \(nq\) both > 5. They may use a number bigger than 5
or they may work out the exact value 0.7148 using the binomial distribution.
Do not allow \(np \gt 5\) and \(npq \gt 5\)