Foundation November 2022 Paper 3 Q10
10 Two supermarkets, A and B, have special offers on the same packet of biscuits.
| Supermarket A | Supermarket B |
|---|---|
| Normal price: £1.50 for each packet Special offer: Buy two packets at the normal price and get a third packet for half price | Normal price: £1.60 for each packet Special offer: 10% off the normal price |
(a) Dan buys one packet of these biscuits.
Which supermarket is best value for Dan?
Show how you decide.
Supermarket .................... because ........................................ [3]
(b) Darcy buys three packets of these biscuits.
Which supermarket is best value for Darcy?
Show how you decide.
Supermarket .................... because ........................................ [3]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| B and 1.44 is less than 1.5[0] oe or B and ([0].06 or 6p) cheaper oe or B and 1.44 and 1.5[0] seen in final statement | 3 | M2 for \(1.6[0] \times 0.9\) oe implied by 1.44 or M1 for \(1.6[0] \times 0.1\) oe implied by [0].16 | Allow B and “It’s cheaper oe” if only 1.44 [and 1.50] seen in working space Accept all figures in pence May be \(1.6[0] - 1.6[0] \times 0.1\) oe M0 for 10% of 1.6[0] See Appendix B and 3.75 and 4.32 only scores 0 B and 1.44 and 3.75 scores M2 only |
Appendix
Appendix for 10a
| Working and answer | Mark | Reason |
|---|---|---|
| 3.75 and 4.32 seen in working Answer: B it is cheaper because 1.44 is cheaper than 1.5 | 3 | Answer uses correct figures |
| 1.44 only seen in working Answer: B it costs less | 3 | There can be no other figure to compare with so all marks awarded |
| 1.44, 3.75 and 4.32 seen in working Answer: B He only wants one packet so it is cheaper | M2 | M2 for 1.44 but no comparison |
| 1.44 and 3.75 seen in working Answer: B even when you buy 2 packets it is cheaper than A | M2 | M2 for 1.44 but no comparison |
| Answer: B and 1.44 cheaper than 3.75 | M2 | Answer based on incorrect figures but 1.44 seen |
| 16p found and 3.75 seen Answer: B and 3.59 cheaper | M1 | 16p seen but 3.59 comes from 3.75 – 0.16 so incorrect values. M1 as 16p used |
| Answer: B and 3.75 lower than 4.32 | 0 | Answer based on incorrect values |
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| A and 3.75 less than 4.32 oe or A and [0].57 saved oe or A and 3.75 and 4.32 seen in final statement OR A and 1.25 less than 1.44 oe or A and 0.19 oe saved or A and 1.25 and 1.44 seen in final statement | 3 | Method 1 M1 for \(1.5 \times 2.5\) oe or 3.75 oe M1 for their \(1.44 \times 3\) or \((3 \times 1.6) \times 0.9\) oe or 4.32 oe Method 2 M2 for \(1.5 \times 2.5 \div 3\) oe or 1.25 or M1 for \(1.5 \times 2.5\) oe or 3.75 | Ignore other figures/statements that don’t invalidate answer All values may be seen in (a) oe may be \(1.5 + 1.5 + 1.5 \div 2\) Allow “A because it’s cheaper” oe if 3.75 and 4.32 only seen as final costs in working space for (b) Allow “A because it’s cheaper” oe if 1.25 and 1.44 only seen as final costs in working space for (b) |