Higher November 2021 Paper 6 Q13
13 A straight line passes through the point (8, 1) and is perpendicular to the line \(y = 4x - 2\).
Find the equation of the line, giving your answer in the form \(y = mx + c\). [4]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(y = -\dfrac{x}{4} + 3\) oe simplified form | 4 | B3 for correct equation not in required form OR B1 for gradient of perp line \(= -\dfrac{1}{4}\) oe soi M1 for \(y - 1 = \textit{their grad} \times (x - 8)\) or \(1 = \textit{their grad} \times 8 + c\) M1 for correct simplification to \(y = mx + c\) form of their \(y - 1 = \textit{their grad} \times (x - 8)\) or using their \(c = 1 - \textit{their grad} \times 8\) | Their grad may be 4, ie they are finding the equation of the parallel line Max M1 if their grad is ‘m’ |