Higher June 2019 Paper 1 Q19
19 The table gives information about the heights of some trees.
| Height (\(h\) metres) | Frequency |
|---|---|
| \(0 \lt h \leqslant 20\) | 15 |
| \(20 \lt h \leqslant 35\) | 48 |
| \(35 \lt h \leqslant 40\) | 21 |
| \(40 \lt h \leqslant 50\) | 16 |
On the grid, draw a histogram for this information.

(3)
| Scheme | Marks |
|---|---|
![]() 48 ÷ 15 (=3.2) 21 ÷ 5 (=4.2) 16 ÷ 10 (=1.6) Answer: correct histogram | B3 |
| (3) | |
| (3 marks) |
Notes
B3: For a fully correct histogram
[If not B3 then B2 for 3 correct frequency densities (can be implied by heights) or 3 correct bars drawn
If not B2 then B1 for 2 correctly calculated frequency densities (can be implied by heights) or 2 correct bars drawn.]
