Higher January 2019 Paper 2R Q8
8
(a) Simplify fully \(\dfrac{15k^4m^3}{5km^2}\) (2)
(b) Solve the inequality \(7 \lt 4x - 1 \leqslant 17\) (3)
| Scheme | Marks |
|---|---|
| \(3k^3m\) | B2 |
| (2) |
Notes
B2: B1 for an answer in the form \(ak^xm^y\) with 2 correct from
\(a = 3\), \(x = 3\), \(y = 1\)
| Scheme | Marks |
|---|---|
| \(7 + 1 \lt 4x \leqslant 17 + 1\) or \(\dfrac{7}{4} \lt x - \dfrac{1}{4} \leqslant \dfrac{17}{4}\) | M1 |
\((7+1) \div 4 \lt x \leqslant (17+1) \div 4\) or \(\dfrac{7}{4} + \dfrac{1}{4} \lt x \leqslant \dfrac{17}{4} + \dfrac{1}{4}\) | M1 |
| \(2 \lt x \leqslant 4.5\) | A1 |
| (3) | |
| (5 marks) |
Notes
M1: or one side of the inequality correct, e.g. 2 or 4.5
A1: Accept \(x \gt 2\), \(x \leqslant 4.5\)