Higher June 2022 Paper 2R Q12
12
Diagram NOT accurately drawn
\(ACE\) and \(BCD\) are straight lines.
\(AB\) is parallel to \(DE\)
Work out the value of \(x\)
(3)
| Scheme | Marks |
|---|---|
eg 6 ÷ 1.2 (= 5) or 1.2 ÷ 6 \(\left(= \dfrac{1}{5}\right)\) or \(\dfrac{2x}{1.2} = \dfrac{2x + 9}{6}\) oe or \(\dfrac{2x}{2x + 9} = \dfrac{1.2}{6}\) oe | M1 |
| eg \(\text{``}{5}\text{''} \times 2x = 2x + 9\) or \(2x \times 6 = 1.2(2x + 9)\) oe eg \(12x = 2.4x + 10.8\) or \(9.6x = 10.8\) oe | M1 |
| \(\dfrac{9}{8}\) | A1 |
| (3) | |
| (3 marks) |
Notes
M1: for finding the scale factor or using a correct ratio or fraction method
M1: for setting up an equation in \(x\) and removing denominators
A1: oe eg 1.125 (allow 1.12 or 1.13)