Foundation June 2025 Paper 2 Q12
12
(a) A straight line has equation \(y = 5x + 2\).
(i) Write down the gradient of the line. [1]
(ii) Find the value of \(y\) when \(x = 7\). [1]
(b) Make \(x\) the subject of \(y = 5x + 2\). [2]
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| (i) 5 | 1 | Do not allow \(5x\) or \(\dfrac{5}{1}\) | |
| (ii) 37 | 1 | ||
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(x = \dfrac{y - 2}{5}\) oe final answer | 2 | M1 for \(y - 2 = 5x\) or for \(\dfrac{y}{5} = x + \dfrac{2}{5}\) or for answer \(\dfrac{y - 2}{5}\) | Allow for 2 marks: \(x = \dfrac{2 - y}{-5}\) and \(x = \dfrac{y}{5} - \dfrac{2}{5}\) If final answer \(x = y - 2/5\) but \(x = \dfrac{y - 2}{5}\) is clearly seen in their working award 2 marks |
| If 0 scored SC1 for correct step to final answer FT incorrect first step | SC1 only awarded for 2 step attempts and where their answer \(x =\) includes 2, 5 and \(y\) Incorrect first step must be seen and then correct step to their final answer for SC1 | ||