Higher November 2024 Paper 6 Q16
16 Work out the exact value of \(x\) in this triangle. [4]
Not to scale
| Answer | Marks | Part marks and guidance | |
|---|---|---|---|
| \(\sqrt{31}\) final answer | 4 | B3 for answer 31 nfww OR B1 for \(\cos 30 = \frac{\sqrt{3}}{2}\) and M2 for \(x^2 = (6\sqrt{3})^2 + 7^2 - 2 \times 6\sqrt{3} \times 7\cos 30\) or better or M1 for other correct arrangements of cosine rule where \(x\) or \(x^2\) are not the subject | Do not accept work in decimals rounded to answers of \(\sqrt{31}\) or 31 Award if seen as clear statement of fact or in use; once seen condone replacement by 0.866… or 0.87 in subsequent work Condone missing brackets Condone use of 10.39… or 10.4 and 0.866… or 0.87 in M2 and M1 |