Foundation June 2022 Paper 2 Q27
27
(i) Factorise \(x^2 + 5x - 24\) (2)
(ii) Hence, solve \(x^2 + 5x - 24 = 0\) (1)
| Scheme | Marks |
|---|---|
| \((x \pm 3)(x \pm 8)\) | M1 |
| \((x - 3)(x + 8)\) | A1 |
| (2) |
Notes
M1: or \((x + a)(x + b)\) where \(ab = -24\) or \(a + b = 5\)
| Scheme | Marks |
|---|---|
| 3, \(-8\) | B1ft |
| (1) | |
| (3 marks) |
Notes
B1ft: Must ft from their answer to (i)
ft from their incorrect factors in the form \((x + a)(x + b)\)