Higher November 2021 Paper 1 Q18
18 Here is trapezium \(ABCD\).
The area of the trapezium is 66 cm2
the length of \(AB\) : the length of \(CD = 2 : 3\)
Find the length of \(AB\). (5)
| Answer | Mark | Mark scheme |
|---|---|---|
| 17.6 | P1 | for correct trig statement, eg \(\sin 30 = \dfrac{h}{6}\) |
| P1 | for complete process to find \(h\), eg \(6 \times \dfrac{1}{2}\ (= 3)\) | |
| P1 | for correct substitution into the area of a trapezium formula, eg \(\dfrac{1}{2}(a + b) \times \text{``}3\text{''} = 66\) or \(a + b = 44\) or \(\dfrac{1}{2}(2x + 3x) \times h = 66\) | |
| P1 | for complete correct process to find the length of \(AB\), eg \(\left[\dfrac{66 \times 2}{3} \div (2 + \text{``}3\text{''})\right] \times 2\) | |
| A1 | cao |
Additional guidance
An answer of \(\dfrac{88}{5}\) gets P4 A0