Foundation June 2018 Paper 3 Q12
12 The diagram shows a scale drawing of a tennis court.
The scale of the drawing is 1 : 200
Work out the perimeter of the real tennis court.
Give your answer in metres. (5)
| Answer | Mark | Mark scheme |
|---|---|---|
| 69.2 | B1 | for a correct measurement of either length or width, eg 11.5 (cm) or 5.8 (cm) |
| P1 | for process to find actual dimensions, eg [length] \(\times\ 200\ (= 2300)\) or [width] \(\times\ 200\ (= 1160)\) | |
| P1 | (indep) for process to convert to metres [length in cm] \(\div\ 100\) eg \(\text{``}2300\text{''} \div 100\ (= 23)\) or \(\text{``}1160\text{''} \div 100\ (= 11.6)\) | |
| P1 | (indep) for process to find the perimeter, eg \(\text{``}23\text{''} \times 2 + \text{``}11.6\text{''} \times 2\ (= 69.2)\) or \(\text{``}11.5\text{''} \times 2 + \text{``}5.8\text{''} \times 2\ (= 34.6)\) | |
| A1 | for an answer in the range 67.6 to 70.8 |
Additional guidance
Allow measurements 11.3 to 11.7 cm and 5.6 to 6.0 cm
NB: could work in mm
[length] in the range 11.0 to 12.0
[width] in the range 5.0 to 6.5
NB: could work in mm
This mark can be awarded for the conversion of any amount in cm to m (ie not from an area)
calculations could be in cm or in m and could be scaled or unscaled figures
SC: award 3 marks for an answer in the range 67.6 to 70.8 using measurements outside the above ranges