Foundation June 2018 Paper 1 Q17
17 There are some chocolates in a box.
\(\dfrac{1}{4}\) of the chocolates contain nuts.
The rest of the chocolates do not contain nuts.
Write down the ratio of the number of chocolates that contain nuts to the number of chocolates that do not contain nuts.
Give your answer in the form \(1 : n\) (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| 1 : 3 | M1 | for \(\dfrac{1}{4} : \dfrac{3}{4}\) oe OR for any correct un-simplified ratio, eg 25 : 75 |
| A1 | cao SC: B1 for an answer of 3 : 1 or \(1 : \dfrac{1}{3}\) if M0 scored |
Additional guidance
Ignore ‘units’ such as 1 nuts : 3 no nuts
\(1 : 3n\) gets M1A0