Foundation November 2018 Paper 2 Q14
14 Victoria throws an ordinary fair 6-sided dice once.
She says,
“The probability of getting a 3 is half the probability of getting a 6”
(a) Is Victoria correct?
You must explain your answer. (1)
You must explain your answer. (1)
Andy throws the dice twice.
He says,
“The probability of getting a 6 on both throws is \(\dfrac{2}{6}\)”
(b) Is Andy correct?
You must explain your answer. (1)
You must explain your answer. (1)
Indre throws the dice once.
She also throws a coin to get Heads or Tails.
(c) List all the possible outcomes she can get. (2)
| Answer | Mark | Mark scheme |
|---|---|---|
| No (supported) | C1 | No and explanation eg “it is \(\dfrac{1}{6}\)” or “each number is the same probability” Acceptable examples No, they are both 1/6 (accept 1 in 6 or 1 : 6 etc) No, they are both the same No, an equal chance No, it’s a fair dice No, there’s only one of each number Not acceptable examples No, it’s an even chance No, it’s 50 – 50 No, 1 : 6 |
| Answer | Mark | Mark scheme |
|---|---|---|
| No (supported) | C1 | No and explanation eg “it is out of 36” or “it is \(\dfrac{1}{6}\) times \(\dfrac{1}{6}\)” Acceptable examples No, the probability is 1/36 No, it’s out of 36 No, he should times not add Not acceptable examples No, it’s \(1/6 \times 1/6\), the probability is 1/12 No, he’s more likely to get it once only No, there’s only one 6 on a dice No, you will have a 2/12 chance |
| Answer | Mark | Mark scheme |
|---|---|---|
| 1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T | B2 | for all 12 outcomes with no extras or repeats |
| (B1 | for at least 6 correct outcomes, ignoring extras and repeats) |
Additional guidance
Pairs must be unambiguous
Accept words and abbreviations