Foundation June 2022 Paper 1 Q16
16 Here is the graph of \(y = 7 - 3x\)
Draw the graph of \(y = 2x + 1\) on the grid
and then
work out an approximate solution to \(7 - 3x = 2x + 1\) [3 marks]
| Answer | Mark | Comments |
|---|---|---|
| At least two points from (0, 1) (1, 3) (2, 5) and (3, 7) | M1 | may be seen in a table of values or embedded in calculations may be implied by correct line \(\pm\dfrac{1}{2}\) square tolerance |
| Correct straight line between (1, 3) and (2, 5) | A1 | \(\pm\dfrac{1}{2}\) square tolerance |
| [1.15, 1.25] from using the graph or 1.2 | B1ft | oe ft \(x\)-coordinate of any line drawn that intersects the given line \(\pm\dfrac{1}{2}\) square tolerance |
Additional guidance
| Ignore further work after B1 scored | |
| 1.2 with M0 scored 1.2 with two correct points seen but no or incorrect line | M0A0B1 M1A0B1 |
| For the A1, ignore incorrect lines unless used to read off for intersection and then only allow for the B1ft | |
| Answer given as coordinates eg (1.2, 3.4) | B0 |