Higher November 2018 Paper 1 Q27

AQACurrent spec2 marksExact Trig & Graphs

27 Here is a sketch of \(\quad y = \cos x \quad\) for values of \(x\) from 0° to 360°

Sketch of y = cos x from 0° to 360°, with a dashed line from the y-axis at height k meeting the curve above the acute angle α° on the x-axis

Not drawn accurately

\(\alpha°\) is an acute angle.

\(\cos \alpha° = k\)

(a) Circle the value of \(\quad \cos(180° - \alpha°)\) [1 mark]
  • \(1 - k\)
  • \(k\)
  • \(-k\)
  • \(-1 - k\)
(b) Circle the value of \(\quad \cos(360° + \alpha°)\) [1 mark]
  • \(k - 1\)
  • \(k + 1\)
  • \(-k\)
  • \(k\)
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